Python program to reverse a number
This program reverses a number entered by user and then it print it on the output screen.Example .If the user enters the number 456,the program will return the output as 654.Here the program using modulus(%) operator to obtain the digits of a number.The original number returned from right to left in the output screen.
Program to reverse a number:
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def reverse(n): d=0 rev=0 while(n>0): d=n%10 n=int(n/10) rev=rev*10+d return rev x=int(input("Enter the number:")) r=reverse(x) print("Reverse of the Number:",r) |
Output
Explanation
The input function used to get the keyboard input from user and int is used to store the user input as numeric in the variable x.Next the function reverse gets called with the input of x and the while loop gets executed until the number greater than zero.
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First iteration: n>0 => 43872>0 (true condition) d = n%10 => 43872%10 => 2 n = n/10 => 43872/10 => 4387 rev = rev*10+d => 0*10+2 => 2 Second iteration n>0=> 4387>0 (true condition) d = 4387%10 => 7 n = 4387/10 => 438 rev = 2*10+7 => 27 Third iteration n>0 => 438>0 (true conditon) d = 438%10 => 8 n = 438/10 => 43 rev = 27*10+8 => 278 Fourth iteration n>0 => 43>0 (true condition) d = 43%10 => 3 n = 43/10 => 4 rev = 278*10+3 = 2783 Fifth iteration n>0 => 4>0 (true condition) d = 4%10 => 4 n = 4/10 = 0 rev = 2783*10+4 =>27834 Sixth iteration n>0 => 0>0 (false condition) |
